"Bergman" meaning in All languages combined

See Bergman on Wiktionary

Noun [Английский]

Etymology: Происходит от ??
  1. английская фамилия
    Sense id: ru-Bergman-en-noun-NU55RNVs
The following are not (yet) sense-disambiguated
Hypernyms: surname

Noun [Шведский]

Forms: неопр., опр. [singular], Им., Bergman [singular], -, Р., Bergmans [singular], -
Etymology: От ??
  1. Бергман (фамилия), кинорежиссёр Ингмар Бергман
    Sense id: ru-Bergman-sv-noun-3Lg7So9g
The following are not (yet) sense-disambiguated
Hypernyms: efternamn
{
  "categories": [
    {
      "kind": "other",
      "name": "Английские существительные",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Английские фамилии/en",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Английский язык",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нет сведений о составе слова",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 7 букв/en",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "Происходит от ??",
  "hypernyms": [
    {
      "sense_index": 1,
      "word": "surname"
    }
  ],
  "lang": "Английский",
  "lang_code": "en",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "английская фамилия"
      ],
      "id": "ru-Bergman-en-noun-NU55RNVs"
    }
  ],
  "word": "Bergman"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "Singularia tantum/sv",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нет сведений о составе слова",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 7 букв/sv",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Средний род/sv",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Фамилии/sv",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Шведские существительные",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Шведский язык",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "От ??",
  "forms": [
    {
      "form": "неопр.",
      "raw_tags": [
        "падеж"
      ]
    },
    {
      "form": "опр.",
      "tags": [
        "singular"
      ]
    },
    {
      "form": "Им.",
      "raw_tags": [
        "падеж"
      ]
    },
    {
      "form": "Bergman",
      "tags": [
        "singular"
      ]
    },
    {
      "form": "-"
    },
    {
      "form": "Р.",
      "raw_tags": [
        "падеж"
      ]
    },
    {
      "form": "Bergmans",
      "tags": [
        "singular"
      ]
    },
    {
      "form": "-"
    }
  ],
  "hypernyms": [
    {
      "sense_index": 1,
      "word": "efternamn"
    }
  ],
  "lang": "Шведский",
  "lang_code": "sv",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "Бергман (фамилия), кинорежиссёр Ингмар Бергман"
      ],
      "id": "ru-Bergman-sv-noun-3Lg7So9g"
    }
  ],
  "tags": [
    "neuter"
  ],
  "word": "Bergman"
}
{
  "categories": [
    "Английские существительные",
    "Английские фамилии/en",
    "Английский язык",
    "Нет сведений о составе слова",
    "Нужна этимология",
    "Слова из 7 букв/en"
  ],
  "etymology_text": "Происходит от ??",
  "hypernyms": [
    {
      "sense_index": 1,
      "word": "surname"
    }
  ],
  "lang": "Английский",
  "lang_code": "en",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "английская фамилия"
      ]
    }
  ],
  "word": "Bergman"
}

{
  "categories": [
    "Singularia tantum/sv",
    "Нет сведений о составе слова",
    "Нужна этимология",
    "Слова из 7 букв/sv",
    "Средний род/sv",
    "Фамилии/sv",
    "Шведские существительные",
    "Шведский язык"
  ],
  "etymology_text": "От ??",
  "forms": [
    {
      "form": "неопр.",
      "raw_tags": [
        "падеж"
      ]
    },
    {
      "form": "опр.",
      "tags": [
        "singular"
      ]
    },
    {
      "form": "Им.",
      "raw_tags": [
        "падеж"
      ]
    },
    {
      "form": "Bergman",
      "tags": [
        "singular"
      ]
    },
    {
      "form": "-"
    },
    {
      "form": "Р.",
      "raw_tags": [
        "падеж"
      ]
    },
    {
      "form": "Bergmans",
      "tags": [
        "singular"
      ]
    },
    {
      "form": "-"
    }
  ],
  "hypernyms": [
    {
      "sense_index": 1,
      "word": "efternamn"
    }
  ],
  "lang": "Шведский",
  "lang_code": "sv",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "Бергман (фамилия), кинорежиссёр Ингмар Бергман"
      ]
    }
  ],
  "tags": [
    "neuter"
  ],
  "word": "Bergman"
}

Download raw JSONL data for Bergman meaning in All languages combined (1.4kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-10-01 from the ruwiktionary dump dated 2024-09-20 using wiktextract (3fd8a50 and 59b8406). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.